2x^2+32-16x=0

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Solution for 2x^2+32-16x=0 equation: 



2x^2+32-16x=0

a = 2; b = -16; c = +32;
Δ = b2-4ac
Δ = -162-4·2·32
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{4}=4$

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